General solution of the Schrodinger equation for a free particle?

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Homework Help Overview

The discussion revolves around the general solution of the Schrödinger equation for a free particle, specifically when the velocity is zero. Participants are exploring the relationship of this equation to concepts learned in class.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses confusion regarding the treatment of the wave function ψ as a function rather than a constant. Some participants discuss the form of the differential equation and its solutions, while others seek clarification on the equation's structure.

Discussion Status

The discussion is ongoing, with participants providing insights into the nature of the differential equation involved. There is an exchange of ideas regarding the correct formulation of the equation, but no consensus has been reached on the interpretation or solution.

Contextual Notes

Participants note the challenge of using LaTeX for equations, which may affect the clarity of the mathematical expressions being discussed.

21joanna12
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Homework Statement


I'm trying to figure out how the general solution of the Schrödinger equation for a free particle when v=0 relates to anything I have learned in class...

Homework Equations


For Eψ=(hbar2/2m)d2ψ/dx2

The Attempt at a Solution


I really have no idea- what is confusing me is that ψ is a function rather than a constant so I don't know how to treat it...

Thank you all for any help!

And I really apologise for the equation... I don't really understand how to use LaTeX
 
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21joanna12 said:

Homework Statement


I'm trying to figure out how the general solution of the Schrödinger equation for a free particle when v=0 relates to anything I have learned in class...

Homework Equations


For [STRIKE]Eψ=(hbar2/2m)d2ψ/dx2
[/STRIKE]

You miss the negative the sign: ##-\hbar^2/(2m)d^2ψ/dx^2=Eψ##

That is a differential equation of form y"+kx=0. What is the solution?

The former equation is the time independent equation for one dimension. The time dependent equation is

##i\hbar \frac{\partial ψ}{\partial t}=-\hbar^2/(2m)\frac{\partial^2}{\partial x^2}##

ehild
 
Last edited:
ehild said:
That is a differential equation of form y"+kx=0.
y"+ky=0?
 
I meant it so. Thanks.

ehild
 

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