Generating current through increasing capacitance

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Homework Help Overview

The discussion revolves around calculating the current generated as a dielectric slab is inserted into a capacitor at a constant rate. The problem involves understanding the relationship between capacitance, charge, and current, with specific variables such as voltage, dielectric constant, and geometry of the capacitor being considered.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the derivation of current in relation to the changing capacitance as the dielectric is inserted. There are attempts to express the current in terms of given variables, and questions arise regarding the inclusion of differential quantities and the correct formulation of the current equation.

Discussion Status

Some participants have offered insights into the mathematical formulation, noting potential errors in the original poster's approach. There is an ongoing exploration of the correct application of differential quantities in the context of the problem, with no explicit consensus reached yet.

Contextual Notes

Participants are grappling with the implications of using differential versus finite quantities in their calculations, and there is an acknowledgment of missing elements in the original formulation that may affect the outcome.

Dilemma
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Hello,

1. Homework Statement

MP_Ch18_Q9_1-300x243.jpg

Assuming that the dielectric is inserted at a constant rate, find the current I as the slab is inserted.
Express your answer in terms of any or all of the given variables V, K, r, d, Δt, and ε0, the permittivity of free space.

Homework Equations


[/B]
C = ε0 * A / d

The Attempt at a Solution


[/B]
Q = CV
dQ = dC ⋅ V

I = dQ/Δt

C = ∈ ⋅ A / d = ∈⋅(xr)K / d + ∈⋅(r-x)r / d
dC = ∈⋅(r)K / d - ∈⋅r / d = ∈r(K-1)/d
dQ = dC⋅V

Therefore answer should be ∈r(K-1)V/(dΔt)

However, the correct answer is ∈(r^2)(K-1)V/(dΔt). That means the multiplier "r" is missing. What is wrong with my solution.

Thanks in advance.

 
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Dilemma said:
dC = ∈⋅(r)K / d - ∈⋅r / d = ∈r(K-1)/d
The left side is a differential quantity. So, the right side should also be a differential quantity.
 
Oops, I have forgotten to include the dx multiplier. Thank you.
 
Dilemma said:
I = dQ/Δt

dQ is a differential quantity, but Δt is the finite amount of time required to completely insert the slab.
Did you mean to write I = dQ/dt, or maybe I = ΔQ/Δt?
 
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