Drama_Queen
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Help me please. Today.. :)
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You have not written the same problem as you show on the Imageshack site.Drama_Queen said:I tried doing c:
2-x/x^2-x X 6x/(2-x)(1+x)
= x-4x)(1+x)
Looks fine, but should be written as (5x + 5)/((2x + 1)(x + 3))Drama_Queen said:--------------
I also tried e:
1(x+3)+2(2x+1)/ (2x+1)(x+3)
x+3+4x+2/ (2x+1)(x+3)
5x+5/ (2x+1)(x+3)
Mistake in next line. The numerator should be (18 - 12x - 6x + 9). When you combine like terms, think about factoring this expression, because you might get some cancellation with one of the factors in the denominator.Drama_Queen said:--------------
I tried f too:
6(3-2x)- 3(2x-3) / (2x-3)(3-2x)
Drama_Queen said:18-12x-6x-9 / (2x-3)(3-2x)
-18x+9 / (2x-3)(3-2x)
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I really need you help. It should be submited tomorrow.
Drama_Queen said:I tried doing c:
2-x/x^2-x X 6x/(2-x)(1+x)
= x-4x)(1+x)--------------
I also tried e:
1(x+3)+2(2x+1)/ (2x+1)(x+3)
x+3+4x+2/ (2x+1)(x+3)
5x+5/ (2x+1)(x+3)
--------------
I tried f too:
6(3-2x)- 3(2x-3) / (2x-3)(3-2x)
18-12x-6x-9 / (2x-3)(3-2x)-18x+9 / (2x-3)(3-2x)
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I really need you help. It should be submited tomorrow.