In the figure R1 = 1.29R, the ammeter resistance is zero, and the battery is ideal. What multiple of ε/R gives the current in the ammeter?
V=IR, 1/R=1/R_1+1/R_2..(when resistances are parallel)
The Attempt at a Solution
since ammeter doesn't have resistance, two top resistances and two bottom resistances are basically parallel. First, I set the currents coming out from the battery is i, and I was getting R_eq
set the voltage as ε
(since two bottom resistances are same, so V_bottom=iR)
i_A=current through ammeter
so I got 0.9847.. for the answer, which is wrong. where did I go wrong? I spent like 3 hours on this problem, and still can't get it.