Getting the tension(Static equilibirum)

  1. 1. The problem statement, all variables and given/known data

    A system cord is knotted at point 0. Determine the angle of the force exerted at cord c If the mass of the hanging block is A=850g(8.34N) the tension in B=42N (the angle of Cord B is 25 degrees from the X-axis)

    The Image: http://tinypic.com/m/5ani0y/3

    2. Relevant equations

    a/sinA = b/sinB = c/sinC


    3. The attempt at a solution

    8.43/sinA = 42/sinB = c/sin65

    so to get the value of c I need to use the cosine law w/c gives me the answer of c=34.544

    If i substitute this value in getting the value of sinA it will be sinA=(34.544)(8.34)/Sin65 w/c gives me a wrong answer.

    Help please
     
    Last edited: Aug 9, 2009
  2. jcsd
  3. How about starting off with the sum of the forces for each component?
     
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