Given force equation, solve for work.

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Homework Help Overview

The problem involves determining the work done by a force described by a vector equation as an object moves from the origin to a specified point. The force components are defined by constants, and the context suggests a focus on the relationship between force, displacement, and work in a physics setting.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the work done by first determining the distance traveled and the force magnitude, but expresses uncertainty about how to proceed with the given information. Some participants question the completeness of the problem statement, noting that the force equation was initially missing. Others suggest breaking down the force and displacement along the axes and integrating to find the work done.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the integration of force over displacement, but no consensus has been reached on the correct approach or solution.

Contextual Notes

There is a noted lack of clarity regarding the complete problem statement, particularly the force equation, which has implications for how participants approach the solution. The original poster also mentions a discrepancy between their calculations and the expected answer.

bfusco
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Homework Statement


Assume that a force acting on an object is given by , where the constants = 2.9 and = 3.9 . Determine the work done on the object by this force as it moves in a straight line from the origin to = (10.0 + 21.5).

The Attempt at a Solution


well... what i did first was i found the length of the tangent of the distance. (using the pythagorean theorem, to get 23.7m).
i don't really know what to do with the other given information. i thought maybe i could plug the given constants into the equation graph and then find the length of the tangent of the force (which i got to be 4.86 N) and then just plug into the equation W=FΔx, but that is incorrect.

apparently the answer is roughly 1000 J, but I am obviously not getting that as my answer.
 
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Hey,i think you missed writing the equation. the entire problem has not been provided
 
emailanmol said:
Hey,i think you missed writing the equation. the entire problem has not been provided

hahahaha...oops sorry the force is given by the equation F=axi+byj (i, j being the components of the force i (hat) and j (hat)). the constants a=2.9 N/m and b=3.9 N/m
 
Hey.

See break force and displacement along the axis.
Force along X axis is given by ax (i)
Remember this force is not a constant and depends on the position of particle on x-axis given by x.

Displacement along x in moving from x to x +dx is given by dx (i)
which makes dW=ax(dx).
Integrate to get workDo similarly for y.

What do you see?
 

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