A particle with charge -5 nC is moving in a uniform magnetic field B = -(1.2 T)k. The magnetic force on the particle is measured to be F = -(3.6*10^(-7) N)i + (7.6*10^-7)j. Calculate the x and y components of the particle's velocity. F = q(V X B) (force equals charge multiplied by the cross product of V and B) Calculate the scalar product (dot product) v*F vx*Fx + vy*Fy + vz*Fz? What is the angle between v and F (in degrees)? F = qvB sin theta theta = arcsin [F/(qvB)]?