Given the diagram, what is the tension in each string?

AI Thread Summary
The discussion focuses on calculating the tension in strings supporting masses, specifically with masses of 1kg and an angle adjustment for T2 at 10°. Participants suggest drawing force diagrams and applying the equations of motion, ∑Fx=max and ∑Fy=may, to analyze the forces. The correct approach involves using sine and cosine functions for the respective x and y components of the tensions. The calculated tension T2 is determined to be approximately 4.97, with further clarification needed for tensions T3 and T4. The conversation emphasizes the importance of accurately applying trigonometric functions in the equations.
laladude
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Homework Statement




Given this diagram and the masses involved, what is the Tension in each string. All masses are 1kg.

Diagram provided

4.jpg


Sorry, the angle for T2 is 10°


Homework Equations





The Attempt at a Solution



I really don't know where to start.
 
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For each mass, draw a force diagram.

Then use ∑Fx=max and ∑Fy=may. (And you should know what ax and ay are :wink:)
 
Redbelly98 said:
For each mass, draw a force diagram.

Then use ∑Fx=max and ∑Fy=may. (And you should know what ax and ay are :wink:)

okay, so for T1 and T2..

x-dir would be ∑Fx = - T1 cos30 + T2 cos10 = 0

y-dir would be ∑Fy = T1 cos30 + T2 cos10 + -mg = 0

Then solve for T1 = T2 cos10/cos30 = 0

Plug into y-dir eq. (T2 cos10/cos30) cos30 + T2 cos10 = mg

T2 = mg/1.97 which is 4.97.

Then plug T2 to T1. Correct?

Now I am uncertain about T3 and T4..
 
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laladude said:
okay, so for T1 and T2..

x-dir would be ∑Fx = - T1 cos30 + T2 cos10 = 0
Yes, good.
y-dir would be ∑Fy = T1 cos30 + T2 cos10 + -mg = 0
Almost -- for the y-dir, we use sin instead of cos.
Then solve for T1 = T2 cos10/cos30 = 0
Except for the "=0" part, that is correct.
Plug into y-dir eq. (T2 cos10/cos30) cos30 + T2 cos10 = mg
Yes, except that there should be some sin's in there because of what I said before about the y-direction forces.
T2 = mg/1.97 which is 4.97.

Then plug T2 to T1. Correct?
Yes, that is the idea.
Now I am uncertain about T3 and T4..
Have a look at the forces acting on Mass #3.
 
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