Given the limit, find F and A?

  • Thread starter Thread starter xzh
  • Start date Start date
  • Tags Tags
    Limit
xzh
Messages
5
Reaction score
0
This limit represents the derivative of some function F at some number A.
lim___________ ([4th root (16+h)] - 2)
_____________________________________
h->0_________________h

f = ?
a = ?

I don't know how to solve this? Teacher said it is going to be on midterms but he never went through it. Thanks.

I think a = 0
 
Physics news on Phys.org
How about f (x) = x1/4, a = 16?
 
hmm, how did you get this? thanks!
losiu99 said:
How about f (x) = x1/4, a = 16?
 
You should start by writing down the definition of the derivative and comparing it to the given limit. You can find the f(a+h) term by looking at where (_+h)'s occur in the given limit
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top