Graduate Engineering - Linear Algebra (Graham Schmidt + more)

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Homework Help Overview

The discussion revolves around the application of the Gram-Schmidt process in linear algebra, specifically in the context of finding vectors that are both in the span of a given set and perpendicular to it. The original poster expresses uncertainty about how to begin the problem using Gram-Schmidt, despite having some understanding of the process and vector addition.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the necessity of using the Gram-Schmidt process versus solving the augmented system directly. There are questions about how to identify vectors that are in the span and perpendicular to it, as well as how to combine these vectors to achieve a specific target vector.

Discussion Status

Some participants have provided insights into the purpose of the Gram-Schmidt process and its implications for forming orthogonal sets of vectors. There is ongoing exploration of how to apply these concepts to the specific problem at hand, with no clear consensus yet on the best approach.

Contextual Notes

Participants note the importance of understanding the relationship between the original set of vectors and the orthogonal set produced by Gram-Schmidt, as well as the conditions under which the vectors must be combined to meet the problem's requirements.

Koolaidbrah
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Homework Statement


5mxo5x.jpg

No idea how to solve this using graham schmidt. I know how to do graham schmidt and how to solve this problem if I didn't have to use graham schmidt, but I have no idea where to start in order to get my vectors to add to V


2e2idzo.jpg

Found c to be 87 by using vector addition/subtraction and making it linearly dependent on other two.
However, not sure how to find two vectors that are in span and perpendicular that add up to V just like in #1



bjieko.jpg

For b., as long as A is invertable, wouldn't it be all of the b vectors?


Homework Equations


Graham Schmidt...



The Attempt at a Solution


Posted above
 
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Well, if the question was not asking you to use the procedure, you could easily solve the augmented system and exhibit a solution.

The point of the gram process though, is to take a set of linearly independent vectors say S, in your space and to form a orthogonal set of vectors T by using the process. The span of the new set of vectors will be equivalent to the span of your original set.

That is, span{T} = span{S}.

You could go even further and form an orthonormal set out of the vectors of T, but it's not required here. Finding the set T should be sufficient.
 
Zondrina said:
Well, if the question was not asking you to use the procedure, you could easily solve the augmented system and exhibit a solution.

The point of the gram process though, is to take a set of linearly independent vectors say S, in your space and to form a orthogonal set of vectors T by using the process. The span of the new set of vectors will be equivalent to the span of your original set.

That is, span{T} = span{S}.

You could go even further and form an orthonormal set out of the vectors of T, but it's not required here. Finding the set T should be sufficient.

Should I use my first two vectors in my set to find the first orthogonal vectors and the third as {1 2 3} to find the vector V2 perpindicular to my span? From there {1 2 3} minus the V2 vector to get my V1

I'm just confused as to how I use V1 is in span, V2 is perp to span and V1+V2 = {1 2 3}
 
Out of curiosity (I'm learning gram schmidt for the first time in my LA class), what application does this have to engineering? (Thinking of going into engineering)
 
Koolaidbrah said:
Should I use my first two vectors in my set to find the first orthogonal vectors and the third as {1 2 3} to find the vector V2 perpindicular to my span? From there {1 2 3} minus the V2 vector to get my V1

I'm just confused as to how I use V1 is in span, V2 is perp to span and V1+V2 = {1 2 3}
Yeah, that'll work if you're planning to do what I think you're saying.
 

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