How Do You Determine Maximum Acceleration from a Velocity-Time Graph?

  • Thread starter Thread starter ProBasket
  • Start date Start date
  • Tags Tags
    Car Graph Sports
AI Thread Summary
To determine maximum acceleration from a velocity-time graph, one must calculate the slope of the velocity function, which represents acceleration. The acceleration is found by identifying changes in velocity over corresponding changes in time, expressed as Δv/Δt. For a calculus-based physics class, this involves using the derivative of the velocity function. If the graph appears complex, using a ruler to measure slopes between points can help clarify the changes in velocity. Understanding these concepts is crucial for accurately determining maximum acceleration.
ProBasket
Messages
140
Reaction score
0
The graph shows the velocity v of a sports car as a function of time t . Use the graph to answer the following questions.

1.) Find the maximum acceleration a_max of the car
Express your answer in meters per second squared to the nearest integer.
a_max= _____________________ m/s^2


from the graph, should the acceleration be around 55m/s? but the answer must be in m/s^2, should am i suppose to convert it first? I'm new to physics, so all of this is pretty confusing.
 

Attachments

  • M1K_va_3.jpg
    M1K_va_3.jpg
    8 KB · Views: 738
Physics news on Phys.org
Is this from a non-calculus based physics class?
 
ProBasket said:
The graph shows the velocity v of a sports car as a function of time t . Use the graph to answer the following questions.

1.) Find the maximum acceleration a_max of the car
Express your answer in meters per second squared to the nearest integer.
a_max= _____________________ m/s^2


from the graph, should the acceleration be around 55m/s? but the answer must be in m/s^2, should am i suppose to convert it first? I'm new to physics, so all of this is pretty confusing.

velocity is in m/s is it not? Acceleration is the change of velocity with respect to a change in time or \Delta v/\Delta t. Loot athe the graph and equate changes in velocity with their corresponding change in time.
 
Is this from a non-calculus based physics class?
it's a cal-based class.

faust9 said:
velocity is in m/s is it not? Acceleration is the change of velocity with respect to a change in time or \Delta v/\Delta t. Loot athe the graph and equate changes in velocity with their corresponding change in time.


how would i find the changes in velocity? it's all over the place. and for time, would the change in time be 1?
 
ProBasket said:
it's a cal-based class.




how would i find the changes in velocity? it's all over the place. and for time, would the change in time be 1?

If this is a calculus based class then you should know that acceleration is the slope of a velocity function.

given a function y(x) then the slope of said function is dy/dx. Given a function of v(t) then the slope is dv/dt which is acceleration.

Think slope and grab a ruler.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top