Graph Solution for u(t)-2u(t-2)+u(t-5) with Heaviside Function

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can someone please help me graph this function:
u(t)-2u(t-2)+u(t-5) where u(t) is heaviside fcn.
i got that it's 1 from 0<t<2 and 1>5 but i don't think that's right but don't know what to do with the 2 in 2u(t-2). thank you.
 
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but don't know what to do with the 2 in 2u(t-2).
You multiply the values of u(t-2) with it.
 
well, obviously but how would that change the graph? would it change the interval, amplitude, or both? can someone please be more specific in their answer. an example, anything.
 
Well, I'm trying to point out that there is nothing unusual going on here: it's just straight arithmetic. I think you're making the problem much harder than it really is: all you have to do is compute the value on each piece.
 
variable said:
well, obviously but how would that change the graph? would it change the interval, amplitude, or both? can someone please be more specific in their answer. an example, anything.

If you multiply any function by 2, what happens to its value?

In particular, the Heaviside function only has values of 0 and 1. Surely you can multiply 0 and 1 by 2!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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