Graphing inequality with mod function

aim1732
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How can we graph this inequality - |y|+1/2>=e-|x| ?
I drew the function(actually a combination of functions) for equality. It would be symmetric in all quadrants and intersect the axes at +ln2 and -ln2(x-axis) and 1/2 and -1/2(y-axis).However since the various graphs are mixed up it is hard pinpoint what region to take.

I have attached one half of the actual graph.
The other half is it's reflection on the x-axis.
 

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aim1732 said:
How can we graph this inequality - |y|+1/2>=e-|x| ?
I drew the function(actually a combination of functions) for equality. It would be symmetric in all quadrants and intersect the axes at +ln2 and -ln2(x-axis) and 1/2 and -1/2(y-axis).However since the various graphs are mixed up it is hard pinpoint what region to take.

I have attached one half of the actual graph.
The other half is it's reflection on the x-axis.
Your inequality is equivalent to |y| >= e-|x| - 1/2. This can be rewritten as
y >= e-|x| - 1/2 or -y >= e-|x| - 1/2

So y >= e-|x| - 1/2 or y <= -e-|x| + 1/2

Does that help?
 
Yes I should have considered the intervals for the different inequalities.Thanks a lot.
 
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