Gravitation Force Between Two Massive Bodies

AI Thread Summary
The discussion centers on calculating the gravitational force exerted by comet Wild2 on the Stardust spacecraft. The spacecraft has a mass of 385 kg, and the comet's nucleus is modeled as a sphere with a diameter of 5 km and a density similar to Pluto's, at 2.1 g/cm^3. To find the comet's mass, the volume of the sphere is calculated, leading to a mass of approximately 13,744 kg. The gravitational force is then computed using the formula F = G(m1 * m2)/R^2, resulting in a force of approximately 6.29 x 10^-15 N. The calculation process is confirmed to be correct, although there is a moment of confusion regarding unit conversions.
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Homework Statement



The Stardust spacecraft was designed to visit a comet and bring samples of its material back to the earth. The craft is 1.7 m across and has a mass of 385 kg. In January 2004, from a distance of 237 km, it took the photograph of the nucleus of comet Wild2, shown in the figure below. The distance across this nucleus is 5 km, and we can model it as an approximate sphere. Since astronomers think that comets have a composition similar to that of Pluto, we can assume a density the same as Pluto's, which is 2.1 g/cm^3. The samples taken will be returned to Earth on Jan. 15, 2006.

What gravitational force did the comet exert on the spacecraft

Homework Equations



F=G ((m1 * m2)/R^2) G= 6.674 x 10 ^-11

The Attempt at a Solution



Well the radius i determined to be 240.35 km. The mass of the satellite is 385 kg. I guess I'm having the problem of determing the mass of the comet. Please Help!
 
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tater08 said:
Since astronomers think that comets have a composition similar to that of Pluto, we can assume a density the same as Pluto's, which is 2.1 g/cm^3.
…
I guess I'm having the problem of determing the mass of the comet.

Hi tater08! :smile:

mass = volume times density. :wink:
 
the volume of a sphere is 4/3 pi (2.5)^3 if the nucleus radius is 5km across the radius is 2.5 km. after converting the 2.1 g/cm^3 to 0.21 kg/m^3. 0.21 kg/m^3 = M/65449.85 m^3 M=13744.47kg F= G (m1 *m2)/R^2 F= (6.674 * 10 ^-11) ((13742.4kg)(385kg))/237000m F=6.29* 10^-15is this right? Thanks for the help!
 
tater08 said:
… after converting the 2.1 g/cm^3 to 0.21 kg/m^3 …

Nooo …
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

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