Gravitation (just to check if calculation is right)

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Homework Help Overview

The discussion revolves around the gravitational interaction between two neutron stars, specifically calculating their speed upon collision given their masses, separation distance, and radii. The problem involves concepts from gravitation and energy conservation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the gravitational force and energy conservation principles to determine the speed of the neutron stars at collision. There are attempts to derive equations for velocity based on gravitational potential energy and kinetic energy. Some participants question the correctness of the equations used.

Discussion Status

The discussion includes various approaches to the problem, with some participants providing alternative methods and questioning assumptions about the equations. There is no explicit consensus on the correct method or outcome, but several lines of reasoning are being explored.

Contextual Notes

Some participants note that they have not covered integrals in their coursework, which may limit their ability to engage with certain methods discussed. There are references to potential energy changes and the need for clarity on the equations being used.

Hollysmoke
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I was wondering if someone could tell me if I did this right:

Two neutron stars are separated by a distance of 10^10m. They each have a mass of 10^30kg and a radius of 10^5m. They are initially at rest relative to each other. How fast are they moving when they collide?

R = 2r + d = 2(10^5)+10^10

v = sqrroot (2Gm2/R^2), sub in all the numbers and v = 1.2x10^5m/s
 
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Hollysmoke said:
I was wondering if someone could tell me if I did this right:

Two neutron stars are separated by a distance of 10^10m. They each have a mass of 10^30kg and a radius of 10^5m. They are initially at rest relative to each other. How fast are they moving when they collide?

R = 2r + d = 2(10^5)+10^10

v = sqrroot (2Gm2/R^2), sub in all the numbers and v = 1.2x10^5m/s

Where did you get "v= sqrroot(2Gm2/R2"? Shouldn't that be v= sqrroot(2Gm2/R)?
 
Hmm I think I rearranged the equation wrong then. Thanks.
 
I did Fg = Gm1m2/r^2 = 1/2mv^2
 
Hollysmoke said:
I was wondering if someone could tell me if I did this right:

Two neutron stars are separated by a distance of 10^10m. They each have a mass of 10^30kg and a radius of 10^5m. They are initially at rest relative to each other. How fast are they moving when they collide?

R = 2r + d = 2(10^5)+10^10

v = sqrroot (2Gm2/R^2), sub in all the numbers and v = 1.2x10^5m/s
The total work done is the integral of the force from initial r to final r:

[tex]\int_{r_i}^{r_f}Fdr = \int_{r_i}^{r_f}\frac{Gm^2}{r^2}dr = Gm^2\left(\frac{1}{r_i} - \frac{1}{r_f}\right)[/tex]

This becomes the kinetic energy of both stars, each of which has half this energy:

[tex]KE_{star} = \frac{1}{2}mv^2 = \frac{1}{2}Gm^2\left(\frac{1}{r_i} - \frac{1}{r_f}\right)[/tex]

[tex]v = \sqrt{Gm\left(\frac{1}{r_i} - \frac{1}{r_f}\right)}[/tex]

AM
 
We haven't done integrals in this unit so I don't know how to solve that method =(
 
Hollysmoke said:
We haven't done integrals in this unit so I don't know how to solve that method =(
All you need to know is that the potential energy is [itex]U = -GmM/r[/itex]. The change in potential energy between two positions is just [itex]\Delta U = -GmM(1/r_f - 1/r_i)[/itex]. This is the change in potential energy of the system. In this case, the system consists of two stars which move toward each other with equal speed.

AM
 

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