Gravitational force between 2 people

AI Thread Summary
To calculate the gravitational force between two students, one weighing 60kg and the other 80kg, separated by 1.4m, the formula Fg = G(m1m2/r^2) is used, with G being 6.67 x 10^-11 Nm^2/kg^2. The user initially miscalculated by using r instead of r^2 in the denominator. Correcting this error is crucial for obtaining the accurate force of attraction. The correct calculation should involve squaring the distance (1.4m) in the denominator. Understanding this formula is essential for solving similar physics problems.
ital_dj
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[SOLVED] Gravitational force between 2 people

OK, this is my first time doing this so I'm completely lost.

Homework Statement


Find the force of attraction between a 60kg student and another student of mass 80kg, 1.4m away.

Homework Equations


G = 6.67 * 10^-11 Nm^2/kg^2

Fg = \frac{Gm_1m_2}{r^2}

The Attempt at a Solution


I tried [6.67 * 10^-11 (60kg)(80kg)] / 1.4m

But I'm wrong.

Your help is appreciated.
 
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r^2, mate; not r.
 
Wow what a mistake.. Thanks a lot!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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