Gravitational potential gradient in accelerated reference frames?

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SUMMARY

The discussion centers on the gravitational potential gradient in accelerated reference frames, specifically addressing the misconception regarding the "speed of time" gradient. It is established that in an accelerating frame, clocks do indeed tick at different rates, which aligns with the concept of gravitational redshift. The equivalence principle indicates that being at rest in a gravitational field and accelerating in flat spacetime are locally indistinguishable, but this does not negate the existence of a time gradient in accelerated frames.

PREREQUISITES
  • Understanding of the equivalence principle in general relativity
  • Familiarity with gravitational redshift concepts
  • Knowledge of accelerated reference frames in physics
  • Basic grasp of time dilation effects
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  • Research the implications of the equivalence principle in general relativity
  • Study the effects of gravitational redshift on timekeeping in different gravitational fields
  • Explore the relationship between acceleration and time dilation in special relativity
  • Examine experimental evidence supporting the concepts of time gradients in accelerated frames
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Physicists, students of general relativity, and anyone interested in the nuances of gravitational fields and accelerated reference frames.

bkercso
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Is there any speed-of-time gradient there?
Hi,

Could you please help me to clarify the following problem? In the gravitational field of a mass, the force on a body in steady state comes from the gradient of the gravitational potential - or the gradient of speed of time. But what about accelerated reference frames? I assume that there is no speed-of-time gradient, right? However, we state that the two type of field are indistunguishable, ie. the same.
 
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bkercso said:
I assume that there is no speed-of-time gradient, right?
You assume wrongly. Calling it a "speed of time" isn't the best way of doing it, but clocks along the length of an accelerating rocket do tick at different rates consistent with a "gravitational redshift".
bkercso said:
However, we state that the two type of field are indistunguishable, ie. the same.
That's not quite accurate. The equivalence principle says that being at rest in a gravitational field and accelerating in flat spacetime are locally indistinguishable. But that doesn't affect my answer above.
 
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