Griffith Intro to QM, 1st order perturb theory in time-dep

AI Thread Summary
The discussion centers on the implications of first-order perturbation theory in time-dependent quantum mechanics, specifically regarding the coefficients ca(t) and cb(t). It highlights a concern that the sum of the squares of these coefficients, ca^2 + cb^2, exceeds one, which seems counterintuitive. The response clarifies that this result is expected at first order and suggests that higher-order corrections are necessary to maintain normalization. It also notes that while the norm conservation implies a modification to ca, it does not provide the actual complex coefficient. Understanding these nuances is crucial for applying time-dependent perturbation theory correctly.
tjsgkdms1111

Homework Statement


ca(0)=1, cb(0)=0
zeroth: ca(t)=1, cb(t)=0
1st: ca(t)=1, cb(t)=i/hbar*integral(H'(t) exp(iwt)) dt
ca^2+cb^2=1 to 1st order of H'.: What does it mean?
it is evidently not 1 at all.

Homework Equations

The Attempt at a Solution

 
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tjsgkdms1111 said:

Homework Statement


ca(0)=1, cb(0)=0
zeroth: ca(t)=1, cb(t)=0
1st: ca(t)=1, cb(t)=i/hbar*integral(H'(t) exp(iwt)) dt
ca^2+cb^2=1 to 1st order of H'.: What does it mean?
it is evidently not 1 at all.

Homework Equations

The Attempt at a Solution

Is this really a homework question, or you don't understand something about TDPT?

While your question is not clear, I get the feeling that you are bothered by the fact that ##|c_a|^2 + |c_b|^2 > 1##, but this is indeed the result you get from 1st-order TDPT. You have to go to higher order to resolve this, or take that by conservation of the norm ##c_a## must be modified such that ##|c_a|^2 = 1 - |c_b|^2 ## (but that only tells you the probability of staying gin the initial state, and not the actual complex coefficient ##c_a##).
 
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