XPTPCREWX said:
The Load?...is this the only reason?
Yes, but this is also the most important reason! The resistance (let's assume that it's purely resistive) CONTROLS THE AMOUNT OF CURRENT that flows through the circuit (from the source to the live wire, through the load, and through neutral, assuming it's working properly). This was, IIRC, the initial question in the other thread. This fact is why your breaker does not trip when you use stuff, because you are not shorting (connecting through a low resistance path) live to neutral. Unless what you're using draws more current than what your breaker is rated for (e.g. a power saw using 20 A on a 15 A circuit--we used to do this all the time when we were cutting through thicker sections of metal).
XPTPCREWX said:
I think I'm getting there...
1. Since the Ground"ED" and Ground"Ing" wire equalize their potential difference at their junction, is it safe to say that they really do short out??
2. So where the Neutral taps into the Delta/Star configuration, is it safe to say this is one of the many faces of "ground".. 0 potential...?
3. Is it safe to assume the ONLY real difference between the grounding wire and the neutral wire is that the neutral wire is the path of "higher" resistance TO ground, and the grounding wire is the path of "least" resistance to ground under normal operating conditions?
4. Is it also safe to assume the Ground"ED" (neutral) and Ground"Ing" wires BOTH end up at "EARTH GROUND" regardless ...and that the only reason for providing a redundant dual path is if the "direct grounding conditions on that plot of land become unstable."...?
Let's go into ideal land and assume 0 wire resistance (since, for the purposes of this explanation, they only complicate the matter without conveying the basics)--as stated previously, the load is what determines current in normal operation.
1) Yes.
2) Don't quite know what you mean by tapping into the DELTA/STAR connection, but if you mean the interface between what the power company gives you and your house, then yes, this point is ground (and with the above 0 wire resistance assumption, actually at Earth ground).
3) No. With the 0 wire resistance assumption, both the neutral and ground wires have the same resistance measured relative to ground: 0! (Not 0 factorial, which is 1, but zero!) I think your confusion in this regards is the same as many people starting out in the AC power biz (and myself, oh so long ago). So let me let you in on a little secret that'll make your life (or analysis, or both if you happen to be an engineer) so much simpler...
You think that there's something special about 'ground', that somehow, it's a power supply with semi-mystical properties. That it is both a supply and sink for electrons (or, the positive charges that Ben Franklin stuck us with). This last point is the one thing that "ground" actually is: a supply and sink of current. However, the amount of current sunk is the same as the amount of current sourced by ground (as it pertains to any circuit). In other words: IT'S A WIRE! :-D
The only thing special about this wire is that it's where we put one lead of our multimeter when we make measurements. Well, that and the fact that it's a really, really big wire, and really easy to connect to: you just jab a 4' copper probe into the (wet) earth, and voila!
4) No, see (1) and (3). Also remember: ground wire shouldn't be carrying current. And if it is: something's wrong (usually, live's connected to earth, or is touching the case, which is also connected to earth).
In regards to the pictures you posted in post 5 of this thread, the actual current flow is most like 1. However, it's like 2 if you use the power of point (3) above, and join the two grounds together, and have the current flowing back to the negative terminal of the power supply. In other words, picture 1 (with part of the wire being earth, instead of your copper metal). Let me end on a pseudo-philosophical point and say: everything goes full circle, current can only flow in loops.