Group Theory (Abstract algebra manipulations)

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Homework Statement


Let a,b,c,d be elements of a group G and let ab = c, bc = d, cd = a, da = b. Examine the expression da^2b and first derive an expression for b in powers of a. Then express c and d in powers of a. Show that a^5 = e (identity element)


Homework Equations





The Attempt at a Solution


So I've been banging me head against this one for a while now. I feel like its something simple and obvious but i can't figure it out. I have an expression for b:

da^2b = daab = (da)(ab) = bc = d

d^-1*daab=d^-1*d
eaab = e
b = a^-2

I can't figure out c or d, well i should say I have worked out values for c and d but know them to be wrong because I can't show a^5 = e. (and also I have the answers to this question)

Thanks
 
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pbxed said:

Homework Statement


Let a,b,c,d be elements of a group G and let ab = c, bc = d, cd = a, da = b. Examine the expression da^2b and first derive an expression for b in powers of a. Then express c and d in powers of a. Show that a^5 = e (identity element)


Homework Equations





The Attempt at a Solution


So I've been banging me head against this one for a while now. I feel like its something simple and obvious but i can't figure it out. I have an expression for b:

da^2b = daab = (da)(ab) = bc = d

d^-1*daab=d^-1*d
eaab = e
b = a^-2

I can't figure out c or d, well i should say I have worked out values for c and d but know them to be wrong because I can't show a^5 = e. (and also I have the answers to this question)

Thanks

You know c=ab. So what happens if you substitute b=a-2 in that equation?
 
Well c = a*a^-2
c=a^-1 right?

Thats the value I got but when I look at the solution its wrong.

Supposedly c = b^-2 = a^4
 
Indeed, that is what we want to prove. You already know that c=a^{-1}. And what we want to prove is that a^{-1}=a^{4}. But to prove that, you will want to calculate d first...
 
Oh, I just worked it out. God I feel dumb.

Thx for your help micromass :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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