Group velocity and the dispersion relation

AI Thread Summary
The discussion focuses on deriving the group velocity from the dispersion relation w=vk, leading to the expression Vg=(c/n)+0.6*c*lambda/n^2. Participants clarify the differentiation process and the application of the chain rule, noting that the final expression is algebraically correct but does not yield a numerical value. There is a debate over whether group velocity can exceed phase velocity, with reminders that group velocity is tied to information transfer and must be less than or equal to the speed of light. The conversation emphasizes the importance of clarity in mathematical presentation, including the orientation of images shared. Overall, the group velocity expression is confirmed as correct in form, but further numerical evaluation is needed.
Kaguro
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Homework Statement
Q.Light of wavelength λ (in free space) propagates through a dispersive medium with refractive index n(λ)=1.5 + 0.6λ. The group velocity of a wave travelling inside this medium in units of 10^8 m/s is
(A) 1.5 (B) 2.0 (C) 3.0 (D)4.0
Relevant Equations
Group velocity is dw/dk. And phase velocity v is w/k.
After noting w=vk and differentiating with respect to k, and lots of simplifying, I get:

Vg = c/n +(2*pi*0.6)/(k*n)

This doesn't correspond to any numerical value though...
 
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You differentiated what with respect to k?
 
kuruman said:
You differentiated what with respect to k?
I differentiated both sides of the equation w=vk w.r.t k

This will give me
dw/dk=v + k(dv/dk)

Group velocity is then dw/dk.
v is c/n the phase velocity..

and then I wrote k=2*pi/lamda
And substituted value of dk.
 
It looks like you did not apply the chain rule correctly.
 
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kuruman said:
It looks like you did not apply the chain rule correctly.
Oh! That's right...

Now the value I get for group velocity is:

Vg=(c/n)+0.6*c*lamda/n^2

Is this correct?

Even so, this is not a numerical answer..
 
Kaguro said:
Oh! That's right...

Now the value I get for group velocity is:

Vg=(c/n)+0.6*c*lamda/n^2

Is this correct?

Even so, this is not a numerical answer..
Look at your expression. It says that group velocity is equal to phase velocity plus something greater than zero. Can the group velocity be greater than the phase velocity? How did you get your answer. Please post the details of your work.
 
15817913115388635755890327047965.jpg


This is my work. Sorry for not typing all this out. That would have taken me hours..
 
The photo is upside down. Next time please post any photos right side up. It's the considerate thing to do.

Your final expression looks algebraically correct.
 
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  • #10
A quick check is to remember that group velocity is related to information transfer, hence it is always less than or equal to the speed of light in vacuum. Phase velocity, on the other hand, does not convey any information and can be greater than c.
 
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