Guess Teacher's Mass: 6.43, 60, 64.3, 600, 643 kg

  • Thread starter Thread starter cupid.callin
  • Start date Start date
  • Tags Tags
    Mass
AI Thread Summary
The discussion centers on determining the teacher's mass recorded with an accuracy of better than 1/2 percent. Participants analyze the implications of this accuracy for the given options: 6.43 kg, 60 kg, 64.3 kg, 600 kg, and 643 kg. It is noted that 0.5% of 60 kg is 0.3 kg, while 64.3 kg has an implied accuracy of +/- 0.1 kg. The conversation emphasizes understanding how to derive error margins for each mass option to identify which conforms to the specified accuracy. Ultimately, the focus is on correctly interpreting the implied uncertainty in measurements.
cupid.callin
Messages
1,130
Reaction score
1

Homework Statement


A teacher measures and records her own mass to an accuracy of better than 1/2 percent. Which of the following is most likely the mass that she recorded?
(A)6.43 kg
(B)60 kg
(C)64.3 kg
(D)600 kg
(E)643 kg



The Attempt at a Solution



i know that answer is either B or C ( quite obvious :D )
but i can't understand how to use the term "to an accuracy of better than 1/2 percent"

.5% of 60 is .3

but what now?
 
Physics news on Phys.org
Numbers have implied accuracy. 64.3 implies measurement accuracy of +/- 0.1 kg unless otherwise stated. 60 kg implies 60 +/- 1 kg. Which one conforms to the stated "within 1/2 a percent" accuracy?
 
64.3 kg?

but how do you come up with error in each given mass?
 
cupid.callin said:
64.3 kg?

but how do you come up with error in each given mass?

Have a look here:

http://www.chem1.com/acad/webtext/pre/mm3.html

Skim down to "Implied Uncertainty".
 
Last edited by a moderator:
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top