What is the effect of the buoyant force on the harmonic oscillator problem?

In summary: When in air, the damping force is a tiny constant (due to the air pressure), whereas in water it is a bit more complicated. Specifically, the linear viscous force is always trying to push the object back to equilibrium, but there is also a bouyant force that tries to push it upwards. So, if you want the object to stay at a certain position, you have to find the value of these two forces that will balance each other out. This is where things get tricky - it's not always easy to tell which one is going to win.
  • #1
PhilT
1
0
I have the following homework problem that I am having trouble with. Any guidance would be appreciated. Thank you in advance.

Consider an object hanging on a spring, immersed in a cup of water. The water
exerts a linear viscous force -bv on the object, where v is the speed of the object
relative to the liquid.
a. The object is displaced vertically from its equilibrium, and is then
released. The cup remains at rest. Find the equation of motion for the
position of the object.
b. Now, the cup is moved up and down. Assuming the motion of the cup is
simple harmonic motion, find the equation of motion for the position of
the object hanging from the spring. Give your answer in terms of the mass
of the object, the spring constant, the damping constant b, the amplitude
through which the cup is moved, and the frequency with which the cup is
moved. Remember that the viscous force depends on the speed of the
object relative to the liquid.
c. What is the steady-state amplitude of oscillation for the object?
d. Now, in addition to moving the cup up and down, we also drive the object
by moving the suspension end of the spring (the opposite end from the one
that the object is attached to). This drive has the same frequency as the
drive that is moving the cup, but it has a different phase. Find the
equation of motion for the object in this case.
e. If the suspension end of the spring is driven with a particular amplitude
and phase, the object will be motionless in steady state. Find the
amplitude and phase for which this occurs.1. Homework Statement

At equilibrium, when the object is at rest in the water the forces acting on it are
mg down
ky and pVg up, with pVg being a bouyant force that is always acting up.
mg-ky-pVg=0 -> mg=pVg+ky

When it starts to move
mg-k(y+x)-bx'+pVg=mx'' -> x''+γx'+ω^2x=2pVg

I am not confident in the effect that the bouyant force has on the mass. Half of the time it is acting as a damping force, half the time as a restoring force, which makes it seem like it would cancel itself out.

So if the effect of the water is just incorporated into the values of the damping force, γ, then the equation of motion would be the same as it is in air, x''+γx'+ω^2x=0.

please let me know if I am missing something. Thanks again!

Phil
 
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  • #2
Hormonic Oscillator Problem
Hormones going up and down aye? I sympathize... have you tried cold showers or playing a sport? ;)

I am not confident in the effect that the bouyant force has on the mass. Half of the time it is acting as a damping force, half the time as a restoring force, which makes it seem like it would cancel itself out.
... how does the buoyant force act as a damping force? Doesn't it always act upwards just like gravity always acts downwards?
 
  • #3
PhilT said:
mg-k(y+x)-bx'+pVg=mx''

To expand on what Simon said. Here your buoyant force is all of a sudden acting in the same direction as gravity wheras in your previous work, it was acting against... So, yes, it will cancel out if you do things correctly.

The big difference to the case of just air is the value of the damping.
 

What is a harmonic oscillator problem?

A harmonic oscillator problem is a mathematical model that describes the motion of a particle that experiences a restoring force proportional to its displacement from equilibrium. It is a common problem in physics and engineering, and has many applications in areas such as mechanics, electromagnetism, and quantum mechanics.

What is the equation of motion for a harmonic oscillator?

The equation of motion for a harmonic oscillator is given by F = -kx, where F is the restoring force, k is the spring constant, and x is the displacement from equilibrium. This equation is derived from Newton's second law of motion, F = ma, where a is the acceleration of the particle.

What is the solution to the harmonic oscillator problem?

The solution to the harmonic oscillator problem depends on the initial conditions of the system. If the particle is given an initial displacement and velocity, the position and velocity at any time t can be calculated using the equations x = A cos(ωt + φ) and v = -Aω sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase angle.

What is the significance of the angular frequency in a harmonic oscillator?

The angular frequency, ω, is a measure of how fast the particle oscillates back and forth. It is related to the mass and spring constant of the system by the equation ω = √(k/m). The higher the angular frequency, the faster the particle oscillates and the shorter the period of the oscillation.

What are some real-life examples of harmonic oscillators?

Harmonic oscillators are present in many everyday objects and systems. Some common examples include a mass attached to a spring, a pendulum, a guitar string, and an electrical circuit with a capacitor and inductor. In each of these systems, the restoring force is proportional to the displacement from equilibrium, making them all harmonic oscillators.

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