Having problems with forces in a static problem

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Homework Help Overview

The discussion revolves around a static problem involving forces acting on a rod, specifically focusing on the roles of tension, friction, weight, and normal force in achieving equilibrium.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the direction of forces, particularly questioning why the normal force might have a horizontal component and how friction contributes to equilibrium. There are attempts to clarify the relationship between normal force and torque.

Discussion Status

The discussion is active, with participants providing insights and corrections regarding the nature of the forces involved. Some guidance has been offered regarding the moments and torque, indicating a productive exploration of the problem.

Contextual Notes

There are indications of confusion regarding the components of the normal force and friction, as well as the conditions for static equilibrium. Participants are navigating through assumptions about force directions and their implications for the system's behavior.

Hernaner28
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I have this situation:

index.php?action=dlattach;topic=59131.0;attach=10647.gif


I know that tension and friction act poining at left. Weight is obviously downward but then I need a force pointing at right for the rod to be static, and the only force left is the normal force but why should it be pointing at left? Isn't it vertical?

Thanks!
 
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why friction is pointing to left if you want equilibrium.
 
No. Normal force has a component to the right. Friction is pointing to left. I think I undeerstand why normal force has a component and it's not vertical only

Thanks!
 
just be careful.normal force is always perpendicular to the direction of motion of point of contact
 
Sorry, I don't get it. What is wrong? Thanks!
 
normal force will be perpendicular to surface ,it does not have left component or right at least in this case.
 
Well then friction should be pointing to left, what are you saying? If friction pointed to right then net torque wouldn't be zero and it would rotate! But if friction pointed to left it would have a translational motion. I need a force pointing to right
 
you will have to take moment about center of mass .normal reaction is opposing that torque.
edit-also if you take moment about point of contact then tension and weight would be counteracting
 
Last edited:
Ahhhhh now I see it. Normal force has a moment! Thank you very much andrien!
 
  • #10
Yeah, that's actually whaat I had to do to calculate the tension force given the fact that I know the weight. After that I can calculate the friction coefficient which doesn't depend on anything, just on the angle theta. It's 0.29 for 60º aproximately
 

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