- #1
Jeff Cook
- 41
- 0
How would one go about solving for C in the following equation?
log ( A - B - C ) = -C + A + B
I have done this...
log ( A - B ) / log ( C ) = -C + A + B
Then...
C + ( log ( A - B ) / log ( C )) = A + B
But I am just shooting in the dark really. Where would one go from here? I would greatly appreciate any help with this.
Thanks,
Jeff
log ( A - B - C ) = -C + A + B
I have done this...
log ( A - B ) / log ( C ) = -C + A + B
Then...
C + ( log ( A - B ) / log ( C )) = A + B
But I am just shooting in the dark really. Where would one go from here? I would greatly appreciate any help with this.
Thanks,
Jeff