Heat energy change when gas compressed

AI Thread Summary
In an isothermal compression of one mole of an ideal gas, a 100 N force moving the piston down 1 m results in 100 J of work done on the gas. The work done is negative, indicating that energy is leaving the system as heat. The internal energy change is zero, leading to the conclusion that 100 J of heat enters the gas. Both heat and work are forms of energy in transit, with energy entering through work and leaving through heat. This highlights the balance of energy transfer in thermodynamic processes.
blueberryfive
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Homework Statement



One mole of an ideal gas is in a container with a moveable piston. A 100 N force moves the piston down 1 m; the compression is isothermal.

Does 100 J of energy leave the gas or enter the gas?

Homework Equations



W=Fd
U=Q-W=Q-P(Vf-Vi)

The Attempt at a Solution



W=P(Vf-Vi). Since Vf<Vi, Vf-Vi<0, so W<0. Hence U=Q-W=Q+W. Since the compression is isothermal, U=0, so 0=Q+W <=> Q=-W <=> Q=100 J. So 100 J of heat enters the gas.
 
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Because the change in the internal energy is zero, as you rightly indicate, we know that no netto energy enters or leaves the system. This can also be seen from Q = W. The work done by the pressure of the gas is negative. This means that heat is leaving the system during the compression.
 
Ok, thanks. If the process weren't isothermal, then heat would enter the gas, right?
 
Not necessarily. We can let heat enter or leave the system by bringing it into contact with a source at a higher or lower temperature, or even isolate it and arrange for an adiabatic compression. Both Q and W signifies energy entering or leaving the system. In this case it enters via W and leaves via Q.
 
blueberryfive said:

Homework Statement



One mole of an ideal gas is in a container with a moveable piston. A 100 N force moves the piston down 1 m; the compression is isothermal.

Does 100 J of energy leave the gas or enter the gas?
Actually, both. Heat Q and work W are both considered "energy in transit." So 100 J energy enters by doing work on the gas, and leaves by removing heat from the gas.

Oops. I guess that's the same as Basic_Physics response. Please disregard.

Chet
 
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