Heat engine/thermal efficiency question

  • Thread starter Thread starter apaerie
  • Start date Start date
  • Tags Tags
    Efficiency Heat
AI Thread Summary
The discussion revolves around calculating the thermal efficiency of a heat engine using a gas with gamma = 1.25 and an initial temperature of 300K. The user initially calculated the thermal efficiency as 18%, which was incorrect, and sought feedback on their approach. It was suggested that the error might stem from significant figures or rounding issues, prompting a request for detailed calculations. Ultimately, the user discovered a miscalculation in their value for QH, which led to the correct answer. The interaction highlights the importance of accurate calculations in thermodynamics.
apaerie
Messages
2
Reaction score
0

Homework Statement


The figure shows the cycle for a heat engine that uses a gas having gamma =1.25. The initial temperature is T1=300K, and this engine operates at 20 cycles per second. What is the engine's thermal efficiency?

[URL]http://session.masteringphysics.com/problemAsset/1074111/3/knight_Figure_19_54.jpg[/URL]


Homework Equations


[PLAIN]http://upload.wikimedia.org/math/7/a/1/7a19ba3fdf776ed7bf92a998cb72996c.png=W[SUB]out[/SUB]/W[SUB]in[/SUB]

[PLAIN]http://upload.wikimedia.org/math/7/a/1/7a19ba3fdf776ed7bf92a998cb72996c.png=1-Q[SUB]c[/SUB]/Q[SUB]H[/SUB]


The Attempt at a Solution


The first question had asked what was the power output of the engine and I managed to get the correct answer for that, so I'm very sure that my values for Q12, Q23, and Q31 are correct. Since Q23 was a positive value, I figured it was the work put in. I then used the power output that I had calculated and divided it by Q23, multiply by a hundred, which gave me 18% which turned out to be wrong.

I then tried the second equation and using the same value (Q23) for QH and adding the absolute values of Q12 and Q31 together to get Qc, divide Qc by QH, and subtracted the result from 1. It still turned out to be 18%, which I already knew was wrong.

So I'm not sure what I'm doing wrong here. Any feedback would be greatly appreciated.
 
Last edited by a moderator:
Physics news on Phys.org
Welcome to Physics Forums.

You're approach looks entirely correct. If this is being checked by submitting online, and you don't know what the "correct" answer is, then there might be some issue with significant figures, or rounding error -- in which case you got the right answer, but it isn't registering.

Can you post your calculations of W12, W23, and the three Q's?

EDIT: I have now worked out the problem, and it is quite different than 18%, so I suspect you calculated the Q's incorrectly. If you show your work, I could help find the error.
 
Last edited:
Redbelly98 said:
Welcome to Physics Forums.

You're approach looks entirely correct. If this is being checked by submitting online, and you don't know what the "correct" answer is, then there might be some issue with significant figures, or rounding error -- in which case you got the right answer, but it isn't registering.

Can you post your calculations of W12, W23, and the three Q's?

EDIT: I have now worked out the problem, and it is quite different than 18%, so I suspect you calculated the Q's incorrectly. If you show your work, I could help find the error.

I figured it out. You're right, I did miscalculate one of the Q's. At the beginning, I calculated QH (or Q23) to be 303J but I know now that was where I went wrong, so I managed to get the right answer now. Thanks for all your trouble :)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top