- #1

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## Homework Statement

given that kλ

^{2}-ρc

_{p}uλ-ρc

_{p}ωi=0

plug into the quadratic formula and get out an equation that looks like this

λ=α+iβ±γ√(1+iδ) where α,β,γ,and δ are in terms of ρ,c

_{p},u,k, and ω

## Homework Equations

(-b±√b

^{2}-4ac)/2a

kλ

^{2}-ρc

_{p}uλ-ρc

_{p}ωi=0

λ=α+iβ±γ√(1+iδ)

## The Attempt at a Solution

so I plugged it in and came out with

(ρc

_{p}u/2k)±(ρc

_{p}u/2k)√1+(4kωi/ρc

_{p}u

^{2})

so γ=(ρc

_{p}u/2k) and δ=(4kω/ρc

_{p}u

^{2})

but I'm unable to make the first term α+iβ and help would be great