Heat of Atomization Ethane: Wavelength to Break C-C Bond

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The heat of atomization for methane is 360 kJ/mol, while for ethane it is 620 kJ/mol, indicating the energy required to break the respective bonds. Ethane contains both C-C and C-H bonds, whereas methane only has C-H bonds. The energy needed to break one C-H bond is calculated to be 90 kJ/mol. To determine the energy for the C-C bond in ethane, the total energy of 620 kJ/mol is used, accounting for the six C-H bonds and one C-C bond. This leads to the conclusion that the energy required to break the C-C bond is approximately 90 kJ/mol.
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Homework Statement


The heat of atomization of methane and ethane are 360kJ/moo and 620kJ/mol, respectively.
The longest wavelength of light capable of breaking the C-C bond is (Avogadro number = 6.02 x 1023, h= 6.62 x 1034J s

Homework Equations


E = hν = hc/λ

The Attempt at a Solution


I think we should consider energy of ethane only as it only has C-C bond.
What is the use of methane energy?
 
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What bonds are present?
 
methane is CH4 and ethane is C2H6. All are single bonds.
 
Let me rephrase the question: bonds between what atoms are present?
 
Bonds between carbon and hydrogen are present in methane and in ethane between carbon and carbon and also carbon and hydrogen.
 
So you have two kinds of bonds. Methane contains only one kind, ethane contains two kinds. Within a good approximation bond energy doesn't depend on the molecule.
 
So now what should I do?
Take E = 360 kJ/mol ?
 
360 kJ/mol is required to break how many bonds between which atoms? How much per this particular kind of bond is it?
 
To break 4 C-H bond we require 360 kJ. For 1 C-H bond it is 90 kJ.
For 6 C-H it is 540 kJ.
So for ethane, heat of atomization is 620 kJ.
So for C-C bond it is 90 kJ/ mol
For 1 C-C bond it is 90 / (6.02 x 1023) kJ
 
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  • #10
Hi!
4 (C-H) bonds require 360kJ/mol...to break them
1×C-C bond+6(C-H) bonds require 620 KJ/mol.
So you can find C-C bond energy.
 
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  • #11
Thanks all of you, got it.
Mooncrater I think we had written the posts at same time, so you don't realized my 9th post?
 
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  • #12
Yup...you're absolutely right..heehee tech sometimes messes things up:)
 
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