Heat transfer through a cylindrical shell

AI Thread Summary
The discussion focuses on calculating the rate of heat flow per unit length through an infinitely long cylindrical shell with inner radius a and outer radius b, maintained at temperatures Ta and Tb. The initial approach involves using the heat transfer equation H = -KA((TH-TC)/L), but the user struggles with determining the correct cross-sectional area A for the cylindrical geometry. It is clarified that the formula is applicable to flat surfaces, and for cylindrical shells, the Laplace equation must be solved in cylindrical coordinates to find the stationary state. The conversation emphasizes that the differential equation used is only valid for one-dimensional heat transfer, making it unsuitable for this scenario unless the shell is very thin. Ultimately, the solution requires adapting to the geometry of the problem rather than relying on flat surface equations.
Ian Baughman
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Homework Statement


An infinitely long cylindrical shell has an inner radius a and outer radius b. If the inside is maintained at a temperature Ta and the outside at a temperature Tb, determine the rate of heat flow per unit length between inner and outer surfaces assuming the shell has a thermal conductivity k.

Homework Equations


[/B]
H = -KA((TH-TC)/L)

The Attempt at a Solution


[/B]
1) I said let TH = Ta and TC = Tb
2) I let L = b-a so my new expression is:
H = -KA((Ta-Tb)/(b-a))​
3) My issue here is I can not figure out what to use for the cross sectional area A. In the example I was using as reference the heat was flowing through the pipe not the outer shell of it so the cross sectional area was easy to calculate.
4) My idea was to use 2πr and multiply it by the length of the shell but since it is an infinitely long cylindrical shell that wouldn't make sense to do.
 
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Your formula is only applicable to heat transfer through a flat surface. To find the stationary state in a different geometry you have to solve the Laplace equation for that geometry.

Also note that you are asked for the transfer per unit length of the cylinder.
 
Orodruin said:
Your formula is only applicable to heat transfer through a flat surface. To find the stationary state in a different geometry you have to solve the Laplace equation for that geometry.

Also note that you are asked for the transfer per unit length of the cylinder.
Do you mean like starting with the definition of heat transfer, H = (dQ/dT) or H = -KA(dT/dx), and solving from there using Laplace?
 
Ian Baughman said:
Do you mean like starting with the definition of heat transfer, H = (dQ/dT) or H = -KA(dT/dx), and solving from there using Laplace?
That differential equation is only valid for heat transfer in one dimension (flat geometry). You cannot apply it here unless your shell is very thin. In general you need to solve the heat equation in cylinder coordinates - which for a stationary situation is equivalent to laplace equation.
 
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