Heavy Pulley / Conservation of Mechanical Energy

AI Thread Summary
The discussion revolves around using conservation of mechanical energy to determine the speed of a block attached to a pulley after it falls a distance d. Participants highlight that the radius of the pulley is not necessary for solving the problem, as the relationship between linear velocity and angular velocity allows for simplification. The equation for conservation of energy can be applied without explicitly knowing the radius, as the terms involving radius will cancel out. The focus is on distributing the change in gravitational potential energy between the linear and rotational kinetic energies. Ultimately, the key takeaway is that the problem can be solved without direct knowledge of the pulley's radius.
danrochester
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Homework Statement


A light inextensible string is wrapped around a cylindrical pulley of mass M that is free to rotate about its axis. The end of the string is attached to a block of mass m. Use conservation of mechanical energy to calculate the speed of the block after it has fallen a distance d starting from rest.



Homework Equations


Well this is the thing, I can easily write the equation for conservation of energy, but at some point I need to know omega, the angular velocity, which I don't think I have any way of knowing.



The Attempt at a Solution


I'm not looking for the answer here, just a hint. I can think of how to do this problem if I knew the radius of the pulley; then I could easily determine omega from v = omega*r. Is there a way to distribute the change in gravitational potential energy between the linear and rotational kinetic energies of the block and pulley that doesn't require any knowledge of the radius of the pulley?
 
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Since v = ωr, you can express the angular velocity in terms of linear velocity. You don't need to know the actual radius.
 
danrochester said:
A light inextensible string is wrapped around a cylindrical pulley of mass M that is free to rotate about its axis.

I can think of how to do this problem if I knew the radius of the pulley; then I could easily determine omega from v = omega*r …

Hi danrochester! :smile:

(have an omega: ω :wink:)

You think you need the r to work out (1/2)Iω2

but actually you can use v on its own, because the r2 in the ω2 cancels out with the r2 in the I. :wink:
 
no crap

haha thanks guys...Sometimes you keep digging until you're too deep to get out, and sometimes you just need to keep digging a liiiittle bit further...
 
Homer Simpson's advice was …

No! Dig up! :biggrin:
 
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