Help Check My Homework: Two Boats & Passenger Speed

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The discussion revolves around a homework problem involving two boats and a passenger's speed relative to the shore. Boat 1 travels north at 3 m/s, while Boat 2 moves at 1.7 m/s at a 40° angle north of east relative to Boat 1. The passenger on Boat 2 walks east at 1.1 m/s relative to Boat 2. The user calculates the resultant speed of the passenger to the shore as approximately 4.74 m/s after setting up the appropriate vectors. Clarification is provided regarding the direction of Boat 1's velocity, confirming that north is indeed the correct orientation for the y-axis.
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I tried looking at the other threads on this but they seem incomplete.
I would like someone to check my work.

Homework Statement


Two boats are heading away from shore. Boat 1 heads due north at a speed of 3 m/s relative to the shore. Relative to Boat 1, Boat 2 is moving 40° north of east at a speed of 1.7 m/s. A passenger on Boat 2 walks due east across the deck at a speed of 1.1 m/s relative to Boat 2. What is the speed of the passenger to the shore?


Homework Equations


x and y vectors.


The Attempt at a Solution


I set up vectors for each moving object.

B1x = 0 B2y = 0

B2x = 1.7cos(40°) B2y = 1.7sin(40°)

Px = 1.1 Py = 0

I added the x and y components

Rx = 0 + 1.302 + 1.1 Ry = 0 + 1.09 + 0

= 2.402 = 1.09

Sp^2 = (2.402)^2 + (1.09)^2
Sp ≈ 4.74 m/s.
 
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If those vectors are the velocities relative to the shore, then surely B1x=0 and B1y=3 m/s ? ( y being East).
 
Mentz114 said:
If those vectors are the velocities relative to the shore, then surely B1x=0 and B1y=3 m/s ? ( y being East).

Don't you mean y being N?
 
haruspex said:
Don't you mean y being N?
On re-reading the question, yes, I mean North.
 
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