[HELP]- Determine the Resultant of the Force System.

[Dellis]

Those two are equivalent. One just factors out the negative sign...

CS

Sorry I just got a bit confused, he presented it in a way not shown to me in the book but yeah it is the same...

post after this one has my calculations done

 

[stewartcs]

Sorry I just got a bit confused, he presented it in a way not shown to me in the book but yeah it is the same...

\Sigma F= -100 lb - 700 lb - 160 lb= -960



R = -(100 + 700 + 160)=-960

No problem...that's why we are here...

CS

 

[Dellis]

No problem...that's why we are here...

CS

I appreciate it, I learned more reading these forums then using this 150 dollar buck, thanks again.

Ok so here the finish line right?...

ΣF= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100(0) - 700(8) - 160(8 + 4)= - 7520 lbX(bar) =ΣM/R.

-7520 lb/-960lb= 7.83 lb

 

[stewartcs]

Ok so here the finish line...

\Sigma F= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100(0) - 700(8) - 160(8 + 4)= - 7520 lb


X(bar) =ΣM/R.

-7520 lb/-960lb= 7.83 lb

Check your units...

CS

 

[Dellis]

Check your units...

CS

Woah I almost forgot about that lil detail, so this is it right.ΣF= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100 lb(0) - 700 lb(8) - 160lb/ft(12)= -7520 lb/ftX(bar) =ΣM/R

-7520 lb/ft (divided by) -960lb= 7.83 ft

 

[stewartcs]

Woah I had forgot about that lil detail, so it is like this

ΣF= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100 lb(0) - 700 lb(8) - 160lb/ft(12)= -7520 lb/ft


X(bar) =ΣM/R.

-7520 lb/ft (divided by) -960lb= 7.83 ft

Correct.

CS

 

[Dellis]

Correct.

CS

Yes!:), thank you all for the guidance in regards to this problem, see now I can do these type of exercises since I understand the process, that is my problem I need to get familiar with the processes.Like I said before I do have two other problems I tried doing by myself and I need them checked/corrected, I will make a new thread since this one is too much already, hopefully you can provide further guidance for those two :).