Help figuring out units in a power fit.

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The equation A = B * V^n is analyzed, where A has units of W/(m^2*K) and V has units of m/s. The parameter n is established as a dimensionless value of 3, while the units for B need to be determined. The correct units for B are confirmed to be W/[m^2 * K * (m/s)^3]. The discussion emphasizes the importance of ensuring all relevant parameters have appropriate units for clarity and accuracy. Understanding these units is crucial for proper application in power fitting.
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The equation of interest is:
A=B*V^n

where A has units of W/(m^2*K)
W=watt, K=kelvin, m=meter
V has units of m/s.

B and n are parameters to be determined.I have a set of values that I put into excel to generate a plot. From the plot, I fit a power trendline to it and got the equation to be
A=20x^3Should B and n have units?
 
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charlies1902 said:
The equation of interest is:
A=B*V^n

where A has units of W/(m^2*K)
W=watt, K=kelvin, m=meter
V has units of m/s.

B and n are parameters to be determined.


I have a set of values that I put into excel to generate a plot. From the plot, I fit a power trendline to it and got the equation to be
A=20x^3


Should B and n have units?

n doesn't have units. It's just 3. But A, B and x should definitely have units. You already know the units for A and x. You just need to find the units for B.
 
Dick said:
n doesn't have units. It's just 3. But A, B and x should definitely have units. You already know the units for A and x. You just need to find the units for B.

it should be (for C):
W/[m^2 * K * (m/s)^3]
where n=3
correct?
 
charlies1902 said:
it should be (for C):
W/[m^2 * K * (m/s)^3]
where n=3
correct?

If you mean the units for B, yes!
 
Dick said:
If you mean the units for B, yes!

Yeah, oops, thanks.
 
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