Help find the force of compression

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The discussion revolves around calculating the forces in a system involving tension in a chain and compression in a support bar, given a mass of 20.4 kg and an angle of 22 degrees. The gravitational force was calculated as 200 N using Fgravity = mg. Tension was determined to be 534 N for the vertical component, while the horizontal component was calculated as 495 N. A free body diagram is suggested as part of the solution process. Overall, the participants express encouragement and confidence in the calculations presented.
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Find the force of tension in the chain. Determine the force of compression in the support bar. Be sure to include a free body diagram as part of your solution.

Now the only information given is a mass=20.4 kg and the angle 22 degrees.

If anyone could help me with this question, it would be greatly appreciated! THANK YOU SO MUCH in advance!


This is what I attempted to do to find a solution:
Fgravity= mg=20.4*9.8=200N

Then to find the tension I did the following:
Tcos(90-22degrees)-200N=0
0.375*T=200N
T=534N------> this would be our vertical component

Resolving horizontally gives:
x-Tcos(22)=0
x=534N*0.927
x=495N
 
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welcome to pf!

hi dani123! welcome to pf! :wink:

(i assume the support bar is horizontal)

yes that's fine :smile:

is anything worrying you about that?​
 
Not anymore! haha I just wasn't feeling very confident with my answer! Thank you very much!
 

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