Help Finding the Tension between 2 Masses

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The discussion revolves around calculating the tension T2 in a system of three blocks connected by strings on a frictionless surface, with specified masses and an applied force on M3. The user has already determined the acceleration using the relationship between the forces and masses, specifically referencing T1 as the tension between M2 and M3. Clarification is sought regarding the acceleration calculation and the positioning of the tensions T1 and T2. The conversation highlights the need for a visual aid to better understand the setup and calculations involved. The focus remains on resolving the tension calculations in the context of the given system dynamics.
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Three blocks on a frictionless surface are connected by massless strings, with M1 = 1.10 kg, M2 = 2.80 kg, and M3 = 3.50 kg. Due to the force F acting on M3, as shown, the system accelerates to the right. Given that T1 is 2.90 N, calculate T2.

I found the acceleration of the problem using F1 = m1 (T1 / (M1 + M2)). Where do I go from here?
 
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So is T1 between M2 and M3, and T2 between M1 and M2?

I don't understand how you got the acceleration... can you describe or upload a picture?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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