Help for physics static and kinetic friction

AI Thread Summary
The discussion revolves around calculating the maximum horizontal force that can be applied to a sled with a penguin on it without causing the penguin to slide off. The penguin weighs 70 Newtons, and the sled weighs 50 Newtons, with static friction between them at 0.671 and kinetic friction between the sled and snow at 0.119. The initial calculations provided were incorrect, particularly in the weight of the penguin and the method for determining the maximum acceleration. Participants emphasized applying Newton's second law to find the correct applied force on the sled, taking into account both the friction forces involved. The conversation highlights the importance of accurately calculating forces and understanding the dynamics of static and kinetic friction in physics problems.
sundeepsingh
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help for physics static and kinetic friction.
Question:
A 70 Newtons Penguin is on a 50 N. sled. the static friction between the penguin and sled is 0.671 and the kinetic friction between the sled and the SNOW is 0.119. FInd the maximum horizontal force that can be applied without the penguin sliding off the sled?
please post the answer A.S.A.p
 
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Hint: What is the maximum value of the static friction that the sled can exert on the penguin? What acceleration is associated with that force? Apply Newton's 2nd law to find the applied force on the sled.
 
this is what i did.
the friction force between sled and snow is= FN X u=(70.1+50)*0.119=14.2919 N.
the friction force between the penguin and sled = (70.1)*0.671=47.0371, therefore, the max horizontal force that can be applied to the sled without causing the penguin to slide off the sled=14.2919+47.0371=61.329 N. But this is wrong, where m i wrong please tell me.
 
Did someone say penguin :D
 
sundeepsingh said:
the friction force between sled and snow is= FN X u=(70.1+50)*0.119=14.2919 N.
OK. (But the penguin weighs 70N, not 70.1N.)
the friction force between the penguin and sled = (70.1)*0.671=47.0371,
OK. (Same comment.)
therefore, the max horizontal force that can be applied to the sled without causing the penguin to slide off the sled=14.2919+47.0371=61.329 N.
Nope. First find the maximum acceleration of the penguin. (What force acts on the penguin?) Then figure out what force must be applied to the sled so that the sled+penguin has that acceleration. (Don't forget to consider the friction force between sled and snow that must be overcome.)
 
THANKS a lot DOC AL, i LUV U lol :P
 
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