Help manipulating integral to use arctan or trig-sub methods

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Homework Statement


∫1/(x2+4)2

Homework Equations


∫dx/(x2+a2)=(1/a)arctan(x/a)+c

The Attempt at a Solution


This looks like an arctan integral or a trig substitution, but in its current form neither would work without manipulation. I'm mainly looking for how to manipulate it to use one of these methods

Thanks!
 
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cjarnutowski said:

Homework Statement


∫1/(x2+4)2


Homework Equations


∫dx/(x2+a2)=(1/a)arctan(x/a)+c


The Attempt at a Solution


This looks like an arctan integral or a trig substitution, but in its current form neither would work without manipulation. I'm mainly looking for how to manipulate it to use one of these methods

Thanks!
Trig substitution is the way to go here. Do you know the substitution to use?
 
I'm only giving this one hint then it's up to you to complete the rest.

square root (a^2 + u^2)

u = a*tan(theta)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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