Help me with easy physics question

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The discussion focuses on the acceleration of a ball thrown straight up at different points in its trajectory. At all points—just after leaving the hand, at the maximum height, and just before hitting the ground—the magnitude of the ball's acceleration is equal to g, which is the acceleration due to gravity. The confusion arises from mixing up acceleration with velocity; while velocity changes, g remains constant. The importance of understanding g as the change in velocity near Earth's surface is emphasized. Clarification is provided that reading the textbook can further aid in understanding these concepts.
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A ball is thrown straight up into the air. At each of the following instants, is the magnitude of the ball's acceleration greater than g, equal to g, less than g, or zero

a) just after leaving your hand? ________

b)At the very top (maximum height)?__________

c) just before hitting the ground?__________
 
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g doesn't change. All of them = g.
 
even though when the ball leaves your hand is still equal to g, wouldn't it be greater??
 
You are thinking about velocity. That changes, but g does not. g is the change in velocity near the surface of earth. If you're still confused you should read your textbook. All of them gives a good description of g.
 
ok thanks i will
 

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