Help on tis quadratic functions question

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The discussion focuses on solving a quadratic function related to the speed of a particle, defined by the equation v = 10t - t². The problem demonstrates that the particle maintains a speed of 5 m/s or greater for exactly 4√5 seconds. The solution involves factoring the quadratic equation and identifying the roots, which are calculated as 5 ± 2√5, confirming the time interval where the speed condition holds true.

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[SOLVED] Help on tis quadratic functions question

Homework Statement


The speed v m/s of a particle traveling from A to B at time t s after leaving A, is given by v =10t-t². the particle starts from rest at A and comes to rest at B. Show that the particle has a speed of 5m/s or greater for exactly 4[tex]\sqrt{5}[/tex] s



Homework Equations


NOne


The Attempt at a Solution



10t-t²>5
t²-10t+5 <0
0.52 < t < 9.47
then i don't know how to do already.
Can someone start me off and guide me along?
 
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consider using the quadratic formula
 
Sigh. You have already solved the problem, but because you are so infatuated with decimal approximations, you don't see the answer even when it stares you in the eye.

On your second line, we factorize the quadratic, with the two zeroes:
[tex]X=\frac{-(-10)\pm\sqrt{(-10)^{2}-4*1*5}}{2*1}=\frac{10\pm\sqrt{80}}{2}=\frac{10\pm\sqrt{16*5}}{2}=5\pm{2}\sqrt{5}[/tex]

You have found that the relevant region lies between these 2 zeroes, and we may then calculate the distance between them:
[tex](5+2\sqrt{5})-(5-2\sqrt{5})=4\sqrt{5}[/tex]
as was to be shown.
 

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