What is the angle between two component vectors with magnitudes 8 and 10?

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To find the angle between two component vectors with magnitudes of 8 and 10, the cosine rule can be applied. The formula used is c² = a² + b² - 2ab*cos(θ), where c is the resultant vector magnitude. By substituting the values, the angle θ can be calculated. The discussion highlights the need for clear formulas to compute the angle and resultant magnitudes. Ultimately, the solution was found elsewhere, indicating the urgency of the query.
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Two component vectors with magnitude of 8 and resultant magnitude of 10. What must be the angle between the two component vectors?

I really don't know where to start on this. Any help would be greatly appreiated!

P.S. need by tomorrow!
 
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Do you have any formulas to compute magnitude of the component vectors and the resultant magnitude?
 
found the answer somewhere else, thanks any way.
 
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Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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