Help Solving Magnetic Flux Question - Can You Assist?

AI Thread Summary
To solve the magnetic flux question, the correct approach involves using the formula Flux = BAcos(theta), where theta is the angle between the magnetic field and the normal to the plane of the square conductor. The magnetic field is oriented 30 degrees above the horizontal, so the angle needed for the calculation is actually 60 degrees (90 degrees - 30 degrees). The magnetic flux through the conductor can then be calculated as Flux = (6T)(2^2)cos(60) = 12. The initial calculation was incorrect due to the misunderstanding of the angle used in the equation. Understanding the relationship between the magnetic field and the area vector is crucial for accurate results.
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I have a question dealing with magnetic flux that I cannot seem to get. Please help

Question= A 2m conductor is formed into a square and placed in the xy plane. a magnetic field is oriented 30 degrees above the horizontal with a strength of 6T. What is the magnetic flux through the conductor?
I would solve this by using the equation: Flux = BAcos(theta) = (6T)(2^2)cos30 = 20.8
however this answer is incorrect. can anyone tell me what I am doing wrong
thanks!
 
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I think you want the angle the field makes with the normal to the plane of the square - not 30 degrees.
 
ok, can you help me find the angle needed for the equation.
 
I would draw a diagram. Draw the plane as a horizontal line, then draw in the normal. Next draw in a line representing the magnetic field, lable the angle between the magnetic field and the plane. You want the angle between the magnetic field and the normal.

Hope this helps :smile:
 
Theta would be the angle between the Field and the Area Vector.

Try using your hands :-)
 

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