- #1

blue88

- 8

- 0

x = (sqrt of 2h/g)v

from these two equations:

h = .5gt^2

x = vt

Thanks... just can't figure this out!

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- Thread starter blue88
- Start date

- #1

blue88

- 8

- 0

x = (sqrt of 2h/g)v

from these two equations:

h = .5gt^2

x = vt

Thanks... just can't figure this out!

- #2

stunner5000pt

- 1,455

- 2

do you mean [tex] \sqrt{\frac{2h}{g}} v [/tex]

Start off with the first equation. Replace what can be replaced in this equation. Rearrange and you're there!

Start off with the first equation. Replace what can be replaced in this equation. Rearrange and you're there!

Last edited:

- #3

blue88

- 8

- 0

yes, this is the formula, it was for a lab so we were using x as a distance

- #4

TD

Homework Helper

- 1,022

- 0

[tex]h = \frac{{gt^2 }}

{2} \Leftrightarrow t^2 = \frac{{2h}}

{g} \Leftrightarrow t = \sqrt {\frac{{2h}}

{g}} [/tex]

All that's left is substituting it in [itex]x = vt[/itex]

- #5

blue88

- 8

- 0

but there is no way to combine the x=vt with it?

- #6

TD

Homework Helper

- 1,022

- 0

That's what you have to do now. Substitute the expression we found for t in the formula x = vt...

- #7

quantumdude

Staff Emeritus

Science Advisor

Gold Member

- 5,575

- 23

Yes, there is. Take [itex]x=vt[/itex] and solve for [itex]t[/itex], then substitute.

- #8

Poncho

- 29

- 0

Are you kiddin' me, buddy? How about [tex]t = \frac{{x}}

{v} [/tex]

{v} [/tex]

- #9

blue88

- 8

- 0

x = (sqrt of 2h/g)v

from these two equations:

h = .5gt^2

x = vt

i still don't understand how to do that

- #10

quantumdude

Staff Emeritus

Science Advisor

Gold Member

- 5,575

- 23

The complete solution is right here in this thread.

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