Engineering Help with Circuits Analysis: V oc & Current Source

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In the discussion about circuit analysis, a newcomer seeks clarification on calculating V_oc and the Thevenin equivalent. It is confirmed that V_oc is equal to the voltage across the current source, but the resistor in question must be included in the R_th calculation despite having no current flow due to the open circuit condition. The importance of accurately redrawing the circuit for clarity is emphasized. The participant acknowledges previous misinformation and appreciates the correction provided by another user. Understanding these concepts is crucial for accurately analyzing circuits and finding Thevenin equivalents.
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I am new to circuits analysis; just wanted to confirm I am doing this problem right:

The partial circuit is attached to this post.

Is V oc equal to the voltage across the current source?
 

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yeah, but as drawn, that resistor has no current, and thus no voltage drop. once it stops being a partial circuit and is attached to other things, then that will change.
 
I guess I should have made it more clear. This is a problem in which we are supposed to find the Thevenin equivalent. I had omitted redrawing the circuit on the farthest left of the diagram ( which is shown by dotted lines). The farthest right of the circuit (where Voc is shown) is supposed to be V Th. Do I still need to count the resistor to the right of the current source in my calculation? I thought there is no current floeing through that resistor since it is an open circuit situation?
 
You're right about Voc, sorry for the misinformation. Voc is the same as the voltage across the current source. The resistor does need to be counted in the Rth calculation, though. I deleted my previous post so I wouldn't confuse anyone else. Thanks for straightening me out Proton Soup. :biggrin:
 

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