Help with coordinate transformations

AI Thread Summary
The discussion centers on understanding coordinate transformations for vector fields, particularly in the context of electrodynamics. The user is confused about how to correctly apply rotations to the vector potential \vec{A} and the resulting magnetic field \vec{B}. They initially calculate \vec{B} as zero in both coordinate systems but later realize that a magnetic field should not appear simply due to a coordinate rotation. The conversation highlights the importance of correctly transforming vector components and emphasizes the need for precision in mathematical expressions. The user seeks advice on identifying sign errors in their calculations, noting that taking breaks sometimes helps them spot mistakes.
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Homework Statement



I'm having trouble understanding coordinate transformations for vector fields. There are two 'coordinate pieces', the coordinates pieces of the vector at a point changes, and the function describing the field can also be rewritten in terms of the new coordinates. I'm having trouble being precise enough in my math to understand this. Precision is the key. So please be as pedantic as you want.

Here's an example for us to work on --
In electrodynamics, given the vector potential \vec{A}, the magnetic field is defined as:
\vec{B} = \nabla \times \vec{A}
In coordinate system number S we have
A_x=x,A_y=0,A_z=0
In coordinate system S', related to S by a rotation about the Z-axis. What is B? Also calculate A, and determine B this way as well.

Homework Equations


\vec{B} = \nabla \times \vec{A}
To change coordinate systems by rotating about the z-axis.
x' = \cos(\theta) x - \sin(\theta) y
y' = \sin(\theta) x + \cos(\theta) y
And the inverse is just
x = \cos(\theta) x' + \sin(\theta) y'
y = -\sin(\theta) x' + \cos(\theta) y'

The Attempt at a Solution



In coordinate system S, we have
\vec{B} = \nabla \times \vec{A} = 0
rotating this vector just trivially gives in S'
\vec{B'} = 0
Now to trying to rotate A
A'_{x'} = \cos(\theta) x,\ A'_{y'} = - \sin(\theta) x,\ A'_{z'} = 0
A'_{x'} = \cos(\theta) (\cos(\theta)x' + \sin(\theta)y'),\ A'_{y'} = - \sin(\theta) (\cos(\theta)x' + \sin(\theta)y'),\ A'_{z'} = 0
But now we have
B'_{x'}=0,\ B'_{y'}=0,\ B'_{z'}=\frac{\partial}{\partial x'} A'_{y'} - \frac{\partial}{\partial y'} A'_{x'} \neq 0
\vec{B'} \neq 0
This disagrees with above, and clearly a magnetic field shouldn't suddenly appear just because I rotated my coordinate system, so I must be doing something wrong.
 
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What you have done is right! You have stumbled upon the fact that the magnetic field B is not really a vector. It is part of a two-tensor called the field strength tensor. Rotation does actually give rise to magnetic field.
 
praharmitra said:
What you have done is right! You have stumbled upon the fact that the magnetic field B is not really a vector. It is part of a two-tensor called the field strength tensor. Rotation does actually give rise to magnetic field.

It does most emphatically NOT! A is a vector. You should have rotated A just like you rotated the coordinates. A_x'=cos(theta)*A_x and A_y'=sin(theta)*A_x. You have a sign mistake. You don't start mixing electric and magnetic fields until you start doing special relativity with boosts. A rotation won't do it.
 
Last edited:
Dick said:
You have a sign mistake.
Doh! It seems so obvious now.

Thanks. I always have trouble finding factors of two and sign errors. Sometimes if I take a break and then work out the problem from scratch, I can fix the errors, but for some reason I can never find them staring at the math ... like my brain skips over it because it "knew what I meant" or something. I have the same problem with spelling mistakes in essays.

Besides just reworking the problem, do you guys have any suggestions from experience for how to find sign errors? Thanks.
 
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