Help With Forces: Determine Force Exerted by 3.2kg Block

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A 27-N force pushes a 6.5-kg block against a 3.2-kg block on a frictionless surface. The initial assumption is that the 3.2-kg block exerts no force on the 6.5-kg block due to zero acceleration. However, the discussion clarifies that the 27-N force affects both blocks, meaning they are in contact and moving together. The force exerted by the 3.2-kg block on the 6.5-kg block must be reconsidered in light of this shared acceleration. Understanding the interaction between the blocks is crucial for solving the problem correctly.
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Ok the problem is:
A 27-N force pushes a 6.5-kg block against a 3.2-kg block. If the blocks are sliding on a horizontal, frictionless surface, determine the force that the 3.2-kg block exerts on the 6.5-kg block.

I'm thinking that the 3.2 block's acceleration equals 0, and so the force would have to equal zero. Does this mean the 3.2 block exerts no force on the 6.5 block?
 
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potatosticks said:
Ok the problem is:
A 27-N force pushes a 6.5-kg block against a 3.2-kg block. If the blocks are sliding on a horizontal, frictionless surface, determine the force that the 3.2-kg block exerts on the 6.5-kg block.

I'm thinking that the 3.2 block's acceleration equals 0, and so the force would have to equal zero. Does this mean the 3.2 block exerts no force on the 6.5 block?
I think you are misreading the problem. The force of 27N pushes BOTH blocks along the table. The blocks are in contact with each other as they slide. Please try it again and report your results.
 
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