Help with Homework Statement 1b: Elasticity & Pressure

AI Thread Summary
In the discussion about homework question 1b on elasticity and pressure, the average force calculated for hailstones striking a window pane is 0.0833N, with an average pressure of 0.0833Pa. When considering the scenario where hailstones strike soft putty instead of a window, the momentum change differs as the stones become embedded, resulting in a change in momentum of mv for each stone. Participants emphasize the need to apply Newton's second law to determine the average force in both scenarios. The conversation focuses on understanding the implications of elastic versus inelastic collisions on momentum and force calculations.
Vexysery
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I need help on question 1b here,

Homework Statement



1. In a one-minute interval, 1000 hailstones, each of mass 0.5 g and speed 10ms-1, strike a
window pane of area 1m2 at an angle of 45°.
(a) If the collisions are elastic, calculate :
(i) the average force and
(ii) the average pressure on the window pane.

(b) How would your answer di ffer if, in Q1, instead of striking a window pane, the
hailstones strike soft putty and are embedded in it?

Homework Equations



Δρ = (mv) - (-mv) = 2mv ? now it is not elastic = mv?
P = F/A = N/V (mv^2) = N/v ΔT A (mv^2) = N/ΔT (mv)
V = v ΔT A

The Attempt at a Solution



I worked out that the average force is 0.0833N and the average pressure is 0.0833Pa. I don't think the force changes at all, but the change of momentum obviously does as there is no rebound. I'm stuck with this and am not sure how to find out how it would change in ai) and aii)

Any help is very much appreciated! Thank you
 
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Vexysery said:
Δρ = (mv) - (-mv) = 2mv

Yes if collision is perfectly elastic.
 
Anybody help please? :)
 
For av F try to use Newton's 2nd law.
 
You already have the change in momentum of one particle.
 
I need help for question 1b, nothing else.

Thanks anyway!
 
If the stones get embedded in the putty one can assume that all the initial momentum becomes zero.

Hence change in momentum = mv for one stone, as you yourself said.
 
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