- #1
bengaltiger14
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Solve: dy/dt = 4y-2, y(0)=3
I first separate variables: dy/(4y-2) = dt
I then integrate both sides to get: ln|4y-2|=t + c
I next set 4y-2=Ce^t
Do I just plug 3 in for y to get C=10 or am I going about this problem the wrong way??
I first separate variables: dy/(4y-2) = dt
I then integrate both sides to get: ln|4y-2|=t + c
I next set 4y-2=Ce^t
Do I just plug 3 in for y to get C=10 or am I going about this problem the wrong way??