Help with Integrating: x^11 e^x / 5x^6

  • Thread starter Thread starter confused88
  • Start date Start date
  • Tags Tags
    Integration
confused88
Messages
22
Reaction score
0

Homework Statement


Can Someone Please Help me integrate the following please...


Homework Equations


- \int x^11 e^x / 5x^6


The Attempt at a Solution


firstly i simplified it to...

-1/5 \int x^5 e^x / 5

Then i did integration by parts,
u = x^5, du = 5x^4, v= e^x, dv= e^x

So i got,

-1/5 [ x^5 e^x \int e^x 5x^4 + C

-1/5 [x^5 e^x - x^5 e^x + C ]

= -1/5C


And this seems insanely wrong :(

Please let me know what I'm doing wrong
 
Physics news on Phys.org
\int5x^{4}e^{x}dx \neq x^{5}e^{x}+C

You're going to have to use integration by parts a few more times...
 
Is there an easier way to do it? Or is integration by parts the only way?
 
I'd say integration by parts is the best way if not the only way. It will be good practice! Good luck and remember to have fun :)
 
hehe okies thanks!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top