- #1
teng125
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integra of (x^2 + y^2)^(3/2) dy is it equals to 2[(x^2 + y^2)^(5/2)] / 10y
??
pls let me know
thanx
??
pls let me know
thanx
Nope, that is not correct. Perhaps if you showed your steps...teng125 said:integra of (x^2 + y^2)^(3/2) dy is it equals to 2[(x^2 + y^2)^(5/2)] / 10y
??
pls let me know
thanx
The formula for integrating (x^2 + y^2)^(3/2) dy is ∫ (x^2 + y^2)^(3/2) dy = 2[(x^2 + y^2)^(5/2)] / 10y + C, where C is the constant of integration.
To solve for y in the equation ∫ (x^2 + y^2)^(3/2) dy = 2[(x^2 + y^2)^(5/2)] / 10y, you can use algebraic manipulation and the fundamental theorem of calculus to isolate y and solve for it.
Yes, there are other methods that can be used to solve this integration, such as substitution, integration by parts, and partial fraction decomposition. However, the chosen method may depend on the specific variables and functions involved in the equation.
No, there is no specific range for the variable y in this integration. However, it is important to note any restrictions or conditions given in the original problem, as they may affect the range of y that can be used in the integration.
The constant of integration, denoted as C, is added to the solution of the integration as it represents all possible solutions that satisfy the given equation. It is important to include the constant of integration in the final answer to account for all possible solutions.